[(2X)+1]-(X+1)=8

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Solution for [(2X)+1]-(X+1)=8 equation: 


Simplifying
[(2X) + 1] + -1(X + 1) = 8

Reorder the terms:
[1 + (2X)] + -1(X + 1) = 8

Remove brackets around [1 + (2X)]
1 + (2X) + -1(X + 1) = 8

Reorder the terms:
1 + (2X) + -1(1 + X) = 8
1 + (2X) + (1 * -1 + X * -1) = 8
1 + (2X) + (-1 + -1X) = 8

Reorder the terms:
1 + -1 + (2X) + -1X = 8

Combine like terms: 1 + -1 = 0
0 + (2X) + -1X = 8
(2X) + -1X = 8

Combine like terms: (2X) + -1X = 1X
1X = 8

Solving
1X = 8

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Divide each side by '1'.
X = 8

Simplifying
X = 8

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